X^2-15x-96=0

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Solution for X^2-15x-96=0 equation: 



X^2-15X-96=0

a = 1; b = -15; c = -96;
Δ = b2-4ac
Δ = -152-4·1·(-96)
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{609}}{2*1}=\frac{15-\sqrt{609}}{2}
$


$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{609}}{2*1}=\frac{15+\sqrt{609}}{2}
$

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